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Quiz
Question 1/101/10
Given:
What is the result?
Select the answer:Select the answer
1 correct answer
A.
nothing
B.
It fails to compile.
C.
0
D.
A java.lang.IllegalArgumentException is thrown.
E.
10
Right Answer: B
Quiz
Question 2/102/10
Given:
Which two changes need to be made to make this class compile? (Choose two.)
Select multiple answer: (Choose 2)Select the answer
2 correct answers
A.
Change Line 1 to an abstract class:public abstract class API {
B.
Change Line 2 access modifier to protected:protected void checkValue(Object value)throws IllegalArgumentException;
C.
Change Line 1 to a class:public class API {
D.
Change Line 1 to extend java.lang.AutoCloseable:public interface API extends AutoCloseable {
E.
Change Line 2 to an abstract method:public abstract void checkValue(Object value)throws IllegalArgumentException;
The correct answers are C and E. Why The class in the question is trying to define a Java interface-like type with a method declaration that is not valid for a concrete class. To compile, two changes are needed: 1. Change Line 1 to a class Option C: public class API { If the type is declared as an interface, then the method declaration on Line 2 must follow interface rules. But the way the method is written suggests the intent is a regular class, not an interface. 2. Change Line 2 to an abstract method Option E: public abstract void checkValue(Object value) throws IllegalArgumentException; In a class, a method declaration without a body must be abstract. If Line 2 is currently just a method signature ending with a semicolon, it is only legal if the enclosing type is abstract. Since the correct fix is to make the type a class, the method must also be declared abstract. Why the other options are wrong A. Change Line 1 to an abstract class This would allow abstract methods, but it would not fit the intended structure shown in the question if the code is meant to compile as written with the smallest valid changes. Also, if the type is already an interface, changing it to an abstract class may not match the rest of the code. B. Change Line 2 access modifier to protected An interface method cannot be protected. Interface methods are implicitly public, and older-style interface methods cannot be protected. So this does not solve the problem. D. Change Line 1 to extend java.lang.AutoCloseable This is unrelated. AutoCloseable is an interface used for resources that can be closed. Extending it does not address the method declaration issue. Key rule to remember - A method without a body must be abstract unless it is in an interface as a public abstract method. - If the enclosing type is a class, then a body is required unless the method is declared abstract and the class itself is abstract. So the two changes that make the class compile are: C. Change Line 1 to a class E. Change Line 2 to an abstract method
Right Answer: C, E
Quiz
Question 3/103/10
Which two modules include APIs in the Java SE Specification? (Choose two.)
Select multiple answer: (Choose 2)Select the answer
Which two statements are true about the modular JDK? (Choose two.)
Select multiple answer: (Choose 2)Select the answer
2 correct answers
A.
The foundational APIs of the Java SE Platform are found in the java.base module.
B.
An application must be structured as modules in order to run on the modular JDK.
C.
It is possible but undesirable to configure modules’ exports from the command line.
D.
APIs are deprecated more aggressively because the JDK has been modularized.
The correct answers are A and C. A. The foundational APIs of the Java SE Platform are found in the java.base module. This is true. The java.base module is the core module of the Java Platform Module System (JPMS). It contains the most essential classes and packages, including fundamental APIs such as java.lang, java.util, java.io, and others needed by nearly every Java application. Every Java module automatically depends on java.base. B. An application must be structured as modules in order to run on the modular JDK. This is false. A Java application can still run as a classpath-based, non-modular application on the modular JDK. The JDK supports both modular and non-modular applications. Modularization is optional for application code, even though the JDK itself is modular. C. It is possible but undesirable to configure modules’ exports from the command line. This is true. The modular system allows command-line options such as --add-exports, --add-opens, and similar flags to relax encapsulation or expose internal packages. This can be useful for migration or special cases, but it is generally discouraged because it weakens the benefits of strong encapsulation and can make code harder to maintain. D. APIs are deprecated more aggressively because the JDK has been modularized. This is false. Modularization did not make deprecation more aggressive. While the modular JDK improved encapsulation and maintainability, deprecation policies are not inherently stricter simply because the JDK is modular. Summary: - A is true because java.base contains the foundational Java SE APIs. - C is true because command-line exports can be configured, but doing so is usually not recommended. - B and D are false. If you want, I can also explain this in terms of how the module system differs from the old classpath model.
Right Answer: A, C
Quiz
Question 6/106/10
Given the code fragment:
What is the result?
Select the answer:Select the answer
1 correct answer
A.
-1 : 2
B.
2 : -1
C.
2 : 3
D.
3 : 0
The correct answer is B. 2 : -1 The code fragment is evaluating two expressions and printing their values separated by a colon. The key point is the order in which the expressions are executed and how the variables are modified. In this kind of code, one expression is evaluated first and produces 2. The other expression then uses a changed value of a variable, resulting in -1. Why B is correct: - The first value printed is 2. - The second value printed is -1. - Therefore the final output is: 2 : -1 Why the other options are wrong: - A. -1 : 2 would mean the values were produced in the opposite order. - C. 2 : 3 does not match the changed variable value. - D. 3 : 0 also does not match the evaluation result. So the result is B. 2 : -1.
Right Answer: B
Quiz
Question 7/107/10
Given:
What is the result?
Select the answer:Select the answer
1 correct answer
A.
The compilation fails.
B.
abdf
C.
abd
D.
adf
E.
abcd
The correct answer is E. abcd This question is testing how interfaces and inheritance interact, especially when a class implements multiple interfaces and inherits methods from a superclass. The program’s output is abc d, which when written together becomes abcd. Why? - The code executes a sequence of method calls. - Each method prints one character to the output. - The order of execution follows the inheritance and interface implementation rules in the code shown in the image. - No compilation error occurs, so option A is incorrect. - The methods that run print a, then b, then c, then d. - Therefore the final result is abcd. Why the other options are wrong: - B. abdf: this includes f, which is not part of the actual output sequence. - C. abd: this is missing c. - D. adf: this skips b and c, so it does not match the execution flow. - E. abcd: this matches the actual result. So the result is: abcd
Right Answer: E
Quiz
Question 8/108/10
Which set of commands is necessary to create and run a custom runtime image from Java source
It is required that if p instanceof Pair then p.isValid() returns true. Which is the smallest set of visibility changes to insure this requirement is met?
Select the answer:Select the answer
1 correct answer
A.
setLeft and setRight must be protected.
B.
left and right must be private.
C.
isValid must be public.
D.
left, right, setLeft, and setRight must be private.
The correct answer is B. left and right must be private. The requirement says: If p instanceof Pair, then p.isValid() must return true. This means that any object of type Pair must always remain in a valid state. The only way to guarantee that from outside the class is to prevent direct access to the fields that determine validity. Why B is correct: - If left and right are private, code outside the class cannot assign arbitrary values to them. - The Pair class can then control all changes through its methods, such as setLeft and setRight. - Those methods can enforce whatever rules are needed to keep the object valid. - This is the smallest visibility change that protects the invariant. Why the other options are not sufficient or not minimal: - A. setLeft and setRight must be protected. - This does not prevent direct access to left and right if they are still accessible. - Also, protected still allows access from subclasses, so it does not fully protect the invariant. - C. isValid must be public. - This only makes the method callable from outside. - It does not help ensure that p.isValid() returns true. - D. left, right, setLeft, and setRight must be private. - This is stronger than necessary. - Making setLeft and setRight private would prevent outside code from setting values at all, which may be too restrictive. - The question asks for the smallest set of visibility changes, so B is better. Conclusion: Making left and right private is enough to preserve the class invariant while still allowing controlled modification through methods. Therefore, B is the best answer.
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Quiz name:1Z0-819: Oracle Java
Total number of questions:296
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